(x^2-x-30)/2=40

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Solution for (x^2-x-30)/2=40 equation: 


x in (-oo:+oo)

(x^2-x-30)/2 = 40 // - 40

(x^2-x-30)/2-40 = 0

(x^2-x-30)/2+(-40*2)/2 = 0

x^2-x-40*2-30 = 0

x^2-x-110 = 0

x^2-x-110 = 0

x^2-x-110 = 0

DELTA = (-1)^2-(-110*1*4)

DELTA = 441

DELTA > 0

x = (441^(1/2)+1)/(1*2) or x = (1-441^(1/2))/(1*2)

x = 11 or x = -10

(x+10)*(x-11) = 0

((x+10)*(x-11))/2 = 0

((x+10)*(x-11))/2 = 0 // * 2

(x+10)*(x-11) = 0

( x+10 )

x+10 = 0 // - 10

x = -10

( x-11 )

x-11 = 0 // + 11

x = 11

x in { -10, 11 }

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